I had to get off of that last page, I looked for hours and read many patents today I am sick of looking at patents geeze, I am slightly wound up here now but at least we have a really strong foundation to write the claims on now. It seems the more stuff in the invention process that becomes, or is, pie in the sky, clouds your ability to write the claims of your invention. So the inventor needs to be crystal clear as to the base foundation of his product to follow, and this get's serious at this point in the design of your product, and you need many factual clarifications in order to progress through the claim writing phase.
We are on this wheel of Fig. 2 "a primary wheel" subparagraph (b) claim 1. and claim 2. First of all the understanding of a few factors involved need to be clarified.
FACTOR ONE :
A wheel used to rotate and continue momentum is called a flywheel for all practicle applications and purposes. This said momentum is a direct and porportional result from rotating the flywheel, and the flywheel is then said to gain a potential inertia, that requires input power from any source of input power that is able to rotate the flywheel. A flywheel that weighs 100lbs. and is starting to be rotated, has two factors at this point. One, is to start the wheel rotating from zero RPS to it's optimum RPS, and it takes more power to start rotation of a flywheel, than to continue rotating it at it's optimum RPS range. To stop the rotation of a flywheel rotating at it's optimum RPS from the ouside circumference takes (x)psi in force of some kind to stop it or restrict it's movement in rotation, and that includes electrical force, hydraulic force, or mechanical force. Now we increase the weight to 200lbs. with another flywheel, and rotate this wheel also at the same revolutions per second as the flywheel that weighed 100lbs. We now stop the 200lb. flywheel and then find our force in (x)psi that was required to stop the flywheel rotation from the outside circumference of the flywheel, is porportionally higher than the (x)psi it took to stop the 100lb. wheel. This wheel is said to have inertia due to momentum. Now as you view the flywheel face as earlier described you will view a circle, in the center of the circle is said to be the center of rotation on the rotating center axis of the flywheel. The distance from the rotating center axis of the flywheel to the outer circumference is the radius. Now lets just say that this flywheel that weighs 200lbs. is 51" in diameter which is also 4.25' . The radius would be half of that so 2.125' would be our multiple, however let's use inches in decimal equivelants which would be 25.5".
Most flywheels are made of a solid piece of metal that has been forged and then machined to size. A 200 pound wheel is very hard to handle and very expensive to have made. A solid flywheel has it's disadvantages in this application of the present invention due to the physical size and weight would limit it's ability to become a competetive design largly due to the effort in shipping and handling alone. Also the solid wheel has fixed weight ratios that become disadvantageous in two case scenarios, a solid wheel has a required power effort to begin to rotate porportional to it's displaced weight over the entire diameter of the circle, and there is no advantage of weight ratio displacement to the outer circumference at the wheels optimum rotational speed.
FACTOR TWO :
It takes less effort porportionally to rotate a wheel by exerting the force to rotate the flywheel on the outer circumference of the flywheel, than it takes to rotate the wheel at the inner most circumference possible. Time and surface speed become an element very interesting to an inventor when it comes to rotating wheels, and in effect rotating wheels are the simplest form of force multipliers when applied efficiently to a mechanical device. Wheels are necessary and can really get complex when dynamic functions are calculated into the equasion. The easier you can rotate a wheel the more efficient it will become.
The "primary wheel" in Fig. 1 as an example shows a side view of the "primary wheel" and attached to it's embodiment is the "twin sheave" read upon in claim 1. subparagraph (h) . Also within this view are two "secondary wheels" read upon in subparagraph (d) and are on each side of the "primary wheel" attached thereto by flexible means (a set of drive belts) one belt to each of the secondary wheels. The twin sheave at this point has a driven diameter of 24" and a radius of 12". So at one foot out from the centerline axis of rotation of the primary wheel the ratio in pressure is one to one when rotating the wheel. Now if the drive power was applied to the outer circumference of the primary wheel you would porportionally reduce the pressure required to rotate the primary wheel. Inversely as the drive diameter goes less it requires porportionally more pressure to rotate the primary wheel. The variable applied to this situation is the fact that the primary wheel will take less pressure to rotate after the optimum RPS is reached on the flywheel, this is called a dynamic variable that constantly changes, and that the variables effecting the power required to rotate any given flywheel are size, weight, shape and rotational speed of the flywheel.